What is the answer to solvefor x,xy=2(x+y-1) ?

The answer to solvefor x,xy=2(x+y-1) is x=(2y-2)/(y-2);\quad y\ne 2

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solvefor x,xy=2(x+y-1)

solve for

x, x y = 2 (x + y - 1)

x = \frac{2 y - 2}{y - 2}; y \neq = 2

Solution steps

x y = 2 (x + y - 1)

Expand

2 (x + y - 1) : 2 x + 2 y - 2

x y = 2 x + 2 y - 2

Move

2 x

to the left side

x y - 2 x = 2 y - 2

Factor

x y - 2 x : x (y - 2)

x (y - 2) = 2 y - 2

Divide both sides by

y - 2; y \neq = 2

x = \frac{2 y - 2}{y - 2}; y \neq = 2

\frac{1}{3} x + 3 = 2

a_{5} = 4 + (- 1)^{5}

x + \frac{2}{5} + \frac{1}{2} + \frac{1}{4} = \frac{3}{10} - \frac{3}{5}

\frac{3}{2} x = 2

8 x - 3 (2 x + 5) = 13

What is the answer to solvefor x,xy=2(x+y-1) ?
The answer to solvefor x,xy=2(x+y-1) is x=(2y-2)/(y-2);\quad y\ne 2