What is the answer to solvefor y,x^2(x+y)=(x-y) ?

The answer to solvefor y,x^2(x+y)=(x-y) is y=(x-x^3)/(x^2+1);\quad x\ne i,x\ne-i

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solvefor y,x^2(x+y)=(x-y)

solve for

y, x^{2} (x + y) = (x - y)

y = \frac{x - x ^{3}}{x ^{2} + 1}; x \neq = i, x \neq = - i

Solution steps

x^{2} (x + y) = (x - y)

Expand

x^{2} (x + y) : x^{3} + y x^{2}

Expand

(x - y) : x - y

x^{3} + y x^{2} = x - y

Move

x^{3}

to the right side

y x^{2} = x - y - x^{3}

Move

y

to the left side

y x^{2} + y = x - x^{3}

Factor

y x^{2} + y : y (x^{2} + 1)

y (x^{2} + 1) = x - x^{3}

Divide both sides by

x^{2} + 1; x \neq = i, x \neq = - i

y = \frac{x - x ^{3}}{x ^{2} + 1}; x \neq = i, x \neq = - i

x, f = (f + g) (x)

8 x + 9 = 17

\frac{7 x - 10}{6} + \frac{5 x + 7}{9} = \frac{8 x + 1}{5} - 5

j, r (t) = e^{t} i + 2 e^{t} j + 2 e^{t} k

\frac{x \cdot 10 + 150 - 20}{17} = 35

What is the answer to solvefor y,x^2(x+y)=(x-y) ?
The answer to solvefor y,x^2(x+y)=(x-y) is y=(x-x^3)/(x^2+1);\quad x\ne i,x\ne-i