What is the answer to solvefor x,f^{-1}(x)=x-3 ?

The answer to solvefor x,f^{-1}(x)=x-3 is x=-(3f)/(1-f);\quad f\ne 0,f\ne 1

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solvefor x,f^{-1}(x)=x-3

solve for

x, f^{- 1} (x) = x - 3

x = - \frac{3 f}{1 - f}; f \neq = 0, f \neq = 1

Solution steps

f^{- 1} (x) = x - 3

Expand

f^{- 1} (x) : \frac{x}{f}

\frac{x}{f} = x - 3

Multiply both sides by

f

x = x f - 3 f; f \neq = 0

Move

x f

to the left side

x - x f = - 3 f; f \neq = 0

Factor

x - x f : x (1 - f)

x (1 - f) = - 3 f; f \neq = 0

Divide both sides by

1 - f; f \neq = 0, f \neq = 1

x = - \frac{3 f}{1 - f}; f \neq = 0, f \neq = 1

3 (x + 5) = 24

y = (\frac{1}{5})^{4}

y = (\frac{1}{5})^{0}

\frac{x}{4} + \frac{x}{2} = x + 3 - \frac{x}{3}

2 n - 15 = - 5 n + 4 n

What is the answer to solvefor x,f^{-1}(x)=x-3 ?
The answer to solvefor x,f^{-1}(x)=x-3 is x=-(3f)/(1-f);\quad f\ne 0,f\ne 1