What is the answer to (5x+1)/3-((x+1)^2)/2 =1-(x^2)/2+1/6 ?

The answer to (5x+1)/3-((x+1)^2)/2 =1-(x^2)/2+1/6 is x=2

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(5x+1)/3-((x+1)^2)/2 =1-(x^2)/2+1/6

\frac{5 x + 1}{3} - \frac{( x + 1 ) ^{2}}{2} = 1 - \frac{x ^{2}}{2} + \frac{1}{6}

x = 2

Solution steps

\frac{5 x + 1}{3} - \frac{( x + 1 ) ^{2}}{2} = 1 - \frac{x ^{2}}{2} + \frac{1}{6}

Combine the fractions

1 + \frac{1}{6} : \frac{7}{6}

\frac{5 x + 1}{3} - \frac{( x + 1 ) ^{2}}{2} = \frac{7}{6} - \frac{x ^{2}}{2}

Move

\frac{x ^{2}}{2}

to the left side

\frac{4 x - 1}{6} = \frac{7}{6}

Multiply both sides by

6

4 x - 1 = 7

Move

1

to the right side

4 x = 8

Divide both sides by

4

x = 2

\frac{3 ( 5 - 3 x )}{- 4} = - 15

p = (0.38 \cdot 100) + (0.51 \cdot 200)

3 (x + 1) + 2 = 5 + 2 (x - 1)

2 (3 + 5) = 4 (1 + 3)

z = \frac{( 1 - i ) ^{4} ( 1 - 3 i ) ^{10}}{( 2 + 2 i ) ^{7}}

What is the answer to (5x+1)/3-((x+1)^2)/2 =1-(x^2)/2+1/6 ?
The answer to (5x+1)/3-((x+1)^2)/2 =1-(x^2)/2+1/6 is x=2
Solve for x: (5x+1)/3-((x+1)^2)/2 =1-(x^2)/2+1/6
The solution is x=2