What is the answer to 9x^2-1-(3x-2)^2=0 ?

The answer to 9x^2-1-(3x-2)^2=0 is x= 5/12

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9x^2-1-(3x-2)^2=0

9 x^{2} - 1 - (3 x - 2)^{2} = 0

x = \frac{5}{12}

Decimal Notation

x = 0.41666 \dots

Solution steps

9 x^{2} - 1 - (3 x - 2)^{2} = 0

Move

1

to the right side

9 x^{2} - (3 x - 2)^{2} = 1

Expand

9 x^{2} - (3 x - 2)^{2} : 12 x - 4

12 x - 4 = 1

Move

4

to the right side

12 x = 5

Divide both sides by

12

x = \frac{5}{12}

∣ 5 x + 4 ∣ \geq - 6

\frac{84 + 16}{4} = b

(x^{2} + 1) (x + 5) (x - 3) \leq 0

\frac{2 ^{3}}{2 ^{2}}

x - 41 = 56

What is the answer to 9x^2-1-(3x-2)^2=0 ?
The answer to 9x^2-1-(3x-2)^2=0 is x= 5/12
Solve for x: 9x^2-1-(3x-2)^2=0
The solution is x= 5/12