What is the answer to solvefor a,88=a+b(2)^{-1/8 (0)} ?

The answer to solvefor a,88=a+b(2)^{-1/8 (0)} is a=88-b

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solvefor a,88=a+b(2)^{-1/8 (0)}

solve for

a, 88 = a + b (2)^{- \frac{1}{8} (0)}

a = 88 - b

Solution steps

88 = a + b (2)^{- \frac{1}{8} (0)}

Switch sides

a + b 2^{- \frac{1}{8} 0} = 88

Remove parentheses:

(a) = a

a + b \cdot 2^{- \frac{1}{8} \cdot 0} = 88

b \cdot 2^{- \frac{1}{8} \cdot 0} = b

a + b = 88

Move

b

to the right side

a = 88 - b

2 x + 2 = 2 x + 2

0 = 4 x + 2

\frac{x}{4} - \frac{3}{4} - \frac{3 x}{8} - \frac{5}{8} = \frac{2 x}{5} - \frac{4}{5}

2 x - 3 - x = 10 + 7 x - 4

\frac{x - 4}{3 - 5} = 0

What is the answer to solvefor a,88=a+b(2)^{-1/8 (0)} ?
The answer to solvefor a,88=a+b(2)^{-1/8 (0)} is a=88-b