What is the answer to 1/4+(2x-(3x-1)/8)= 2/3 ((x+2)/6)-2x ?

The answer to 1/4+(2x-(3x-1)/8)= 2/3 ((x+2)/6)-2x is x=-1/23

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1/4+(2x-(3x-1)/8)= 2/3 ((x+2)/6)-2x

\frac{1}{4} + (2 x - \frac{3 x - 1}{8}) = \frac{2}{3} (\frac{x + 2}{6}) - 2 x

x = - \frac{1}{23}

Decimal Notation

x = - 0.04347 \dots

Solution steps

\frac{1}{4} + (2 x - \frac{3 x - 1}{8}) = \frac{2}{3} (\frac{x + 2}{6}) - 2 x

Move

\frac{1}{4}

to the right side

2 x - \frac{3 x - 1}{8} = - \frac{1}{4} + \frac{- 17 x + 2}{9}

Multiply by LCM

144 x - 9 (3 x - 1) = - 18 + 8 (- 17 x + 2)

Expand

- 9 (3 x - 1) : - 27 x + 9

144 x - 27 x + 9 = - 18 + 8 (- 17 x + 2)

Add similar elements:

144 x - 27 x = 117 x

117 x + 9 = - 18 + 8 (- 17 x + 2)

Expand

- 18 + 8 (- 17 x + 2) : - 136 x - 2

117 x + 9 = - 136 x - 2

Move

9

to the right side

117 x = - 136 x - 11

Move

136 x

to the left side

253 x = - 11

Divide both sides by

253

x = - \frac{1}{23}

6 x - 3 (2 x - 5) = 15

7 x - 2 (4 x - 3) = 8 (x + 9) - 30

F, E = F - G

- 2 (- 7 n - 8) = - 39 + 3 n

x, (x - y)^{2} = (x - y) (x - y)

What is the answer to 1/4+(2x-(3x-1)/8)= 2/3 ((x+2)/6)-2x ?
The answer to 1/4+(2x-(3x-1)/8)= 2/3 ((x+2)/6)-2x is x=-1/23
Solve for x: 1/4+(2x-(3x-1)/8)= 2/3 ((x+2)/6)-2x
The solution is x=-1/23