What is the answer to (x+1)/2+(2x-1)/4+(x+2)/3 =1 ?

The answer to (x+1)/2+(2x-1)/4+(x+2)/3 =1 is x= 1/16

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(x+1)/2+(2x-1)/4+(x+2)/3 =1

\frac{x + 1}{2} + \frac{2 x - 1}{4} + \frac{x + 2}{3} = 1

x = \frac{1}{16}

Decimal Notation

x = 0.0625

Solution steps

\frac{x + 1}{2} + \frac{2 x - 1}{4} + \frac{x + 2}{3} = 1

Multiply by LCM

6 (x + 1) + 3 (2 x - 1) + 4 (x + 2) = 12

Expand

6 (x + 1) + 3 (2 x - 1) + 4 (x + 2) : 16 x + 11

16 x + 11 = 12

Move

11

to the right side

16 x = 1

Divide both sides by

16

x = \frac{1}{16}

\frac{( 2 x - 1 )}{3} + \frac{( 3 x + 4 )}{4} = \frac{( 7 x + 21 )}{10}

\frac{x + 3}{4} = \frac{x - 1}{2}

\frac{2}{7} x = 6

3 (w - 2) - 4 w = 2 (w - 9)

\frac{5 x}{6} + \frac{3}{10} = \frac{5 x}{15}

What is the answer to (x+1)/2+(2x-1)/4+(x+2)/3 =1 ?
The answer to (x+1)/2+(2x-1)/4+(x+2)/3 =1 is x= 1/16
Solve for x: (x+1)/2+(2x-1)/4+(x+2)/3 =1
The solution is x= 1/16