What is the answer to solvefor k,k(r)=e^r+r^e ?

The answer to solvefor k,k(r)=e^r+r^e is k=(e^r+r^e)/r ;\quad r\ne 0

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solvefor k,k(r)=e^r+r^e

solve for

k, k (r) = e^{r} + r^{e}

k = \frac{e ^{r} + r ^{e}}{r}; r \neq = 0

Solution steps

k (r) = e^{r} + r^{e}

Divide both sides by

r; r \neq = 0

k = \frac{e ^{r} + r ^{e}}{r}; r \neq = 0

x, x + 2 y + 4 z = 1

11 (\frac{5}{7}) + 5 (\frac{5}{7}) - 1 = 65 (\frac{5}{7}) - 36

x, 2 x + 3 y = 60

3 x + 8 = 5 x + 6

x, 12 x - 20 y = - 40

What is the answer to solvefor k,k(r)=e^r+r^e ?
The answer to solvefor k,k(r)=e^r+r^e is k=(e^r+r^e)/r ;\quad r\ne 0