What is the answer to solvefor x,2x=y(2x-2) ?

The answer to solvefor x,2x=y(2x-2) is x=-y/(1-y);\quad y\ne 1

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solvefor x,2x=y(2x-2)

solve for

x, 2 x = y (2 x - 2)

x = - \frac{y}{1 - y}; y \neq = 1

Solution steps

2 x = y (2 x - 2)

Expand

y (2 x - 2) : 2 x y - 2 y

2 x = 2 x y - 2 y

Move

2 x y

to the left side

2 x - 2 x y = - 2 y

Factor

2 x - 2 x y : 2 x (1 - y)

2 x (1 - y) = - 2 y

Divide both sides by

2 (1 - y); y \neq = 1

x = - \frac{y}{1 - y}; y \neq = 1

\frac{h}{7} + 2 = 12

x, 6 x + 5 y = 12

x, 2 x + z = 2

x, 6 x + 5 y = 93

4 x + x = 180

What is the answer to solvefor x,2x=y(2x-2) ?
The answer to solvefor x,2x=y(2x-2) is x=-y/(1-y);\quad y\ne 1