What is x^2<= |4x-3| ?

The solution to x^2<= |4x-3| is -sqrt(7)-2<= x<= sqrt(7)-2\lor 1<= x<= 3

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x^2<= |4x-3|

x^{2} \leq ∣ 4 x - 3 ∣

- 7 - 2 \leq x \leq 7 - 2 or 1 \leq x \leq 3

Interval Notation

[- 7 - 2, 7 - 2] \cup [1, 3]

Decimal Notation

- 4.64575 \dots \leq x \leq 0.64575 \dots or 1 \leq x \leq 3

Solution steps

x^{2} \leq ∣ 4 x - 3 ∣

Find positive and negative intervals

x < \frac{3}{4}, x \geq \frac{3}{4}

Solve the inequality for each interval

- 7 - 2 \leq x \leq 7 - 2 or 1 \leq x \leq 3

\frac{1}{\frac{2}{7}}

20 x^{2} - 11 x - 3 = 0

3 z - 15 z - 30 > 54

x^{2} - 13 x + 40 > 0

829 (\frac{0.4 2 ^{2}}{2}) (0.42)

What is x^2<= |4x-3| ?
The solution to x^2<= |4x-3| is -sqrt(7)-2<= x<= sqrt(7)-2\lor 1<= x<= 3