What is the answer to (x-2)^2=x^2-4x+4 ?

The answer to (x-2)^2=x^2-4x+4 is True for all x

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(x-2)^2=x^2-4x+4

(x - 2)^{2} = x^{2} - 4 x + 4

True for all x

Solution steps

(x - 2)^{2} = x^{2} - 4 x + 4

Expand

(x - 2)^{2} : x^{2} - 4 x + 4

x^{2} - 4 x + 4 = x^{2} - 4 x + 4

Move

4

to the right side

x^{2} - 4 x = x^{2} - 4 x

Subtract

x^{2} - 4 x

from both sides

x^{2} - 4 x - (x^{2} - 4 x) = x^{2} - 4 x - (x^{2} - 4 x)

Simplify

0 = 0

Both sides are equal

True for all x

3 (7 - 2 n) = - 3 (5 - n)

\frac{4 - x}{5} = x + 2

2 (6) - 20 = 400 - 5 (60) 0

\frac{( b - x )}{a} + \frac{( a x )}{b} + \frac{( x + b )}{2} = x + a

6 (y^{2} - y - 6) - (2 y^{2} + 3 y - 2) = 2 (2 y^{2} - 7 y + 3)

What is the answer to (x-2)^2=x^2-4x+4 ?
The answer to (x-2)^2=x^2-4x+4 is True for all x
Solve for x: (x-2)^2=x^2-4x+4
The solution is True for all x