What is the answer to solvefor x,5x=y^{5/2}+5y^{-1/2} ?

The answer to solvefor x,5x=y^{5/2}+5y^{-1/2} is x=(y^3+5)/(5y^{1/2)}

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solvefor x,5x=y^{5/2}+5y^{-1/2}

solve for

x, 5 x = y^{\frac{5}{2}} + 5 y^{- \frac{1}{2}}

x = \frac{y ^{3} + 5}{5 y ^{\frac{1}{2}}}

Solution steps

5 x = y^{\frac{5}{2}} + 5 y^{- \frac{1}{2}}

Simplify

y^{\frac{5}{2}} + 5 y^{- \frac{1}{2}} : y^{\frac{5}{2}} + \frac{5}{y ^{\frac{1}{2}}}

5 x = y^{\frac{5}{2}} + \frac{5}{y ^{\frac{1}{2}}}

Divide both sides by

5

x = \frac{y ^{3} + 5}{5 y ^{\frac{1}{2}}}

0.05 x = 20

- 3 (4) + 2 (0) = 5

7 (4 x - 8) = - 6 (- 5 x + 7)

y = \frac{3}{4} (- 2) - 1

x + 1 = - 2 x + 4

What is the answer to solvefor x,5x=y^{5/2}+5y^{-1/2} ?
The answer to solvefor x,5x=y^{5/2}+5y^{-1/2} is x=(y^3+5)/(5y^{1/2)}