What is factor x^4+2x^3-7x^2-8x+12 ?

The solution to factor x^4+2x^3-7x^2-8x+12 is (x-1)(x+3)(x+2)(x-2)

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factor x^4+2x^3-7x^2-8x+12

factor

x^{4} + 2 x^{3} - 7 x^{2} - 8 x + 12

(x - 1) (x + 3) (x + 2) (x - 2)

Solution steps

x^{4} + 2 x^{3} - 7 x^{2} - 8 x + 12

Use the rational root theorem

= (x - 1) \frac{x ^{4} + 2 x ^{3} - 7 x ^{2} - 8 x + 12}{x - 1}

\frac{x ^{4} + 2 x ^{3} - 7 x ^{2} - 8 x + 12}{x - 1} = x^{3} + 3 x^{2} - 4 x - 12

= (x - 1) (x^{3} + 3 x^{2} - 4 x - 12)

Factor

x^{3} + 3 x^{2} - 4 x - 12 : (x + 3) (x + 2) (x - 2)

= (x - 1) (x + 3) (x + 2) (x - 2)

\frac{2}{11} \cdot \frac{1}{5}

\frac{x}{6} = \frac{6}{9}

x + \frac{x}{3} \leq 1800

- x^{3} + 2 x^{2} + x - 2

2245

What is factor x^4+2x^3-7x^2-8x+12 ?
The solution to factor x^4+2x^3-7x^2-8x+12 is (x-1)(x+3)(x+2)(x-2)