What is the answer to solvefor x,y=xp+p^2 ?

The answer to solvefor x,y=xp+p^2 is x=(y-p^2)/p ;\quad p\ne 0

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solvefor x,y=xp+p^2

solve for

x, y = x p + p^{2}

x = \frac{y - p ^{2}}{p}; p \neq = 0

Solution steps

y = x p + p^{2}

Switch sides

x p + p^{2} = y

Move

p^{2}

to the right side

x p = y - p^{2}

Divide both sides by

p; p \neq = 0

x = \frac{y - p ^{2}}{p}; p \neq = 0

i, x = sin (x)

- 8 (2 b + 8) + 7 = - 137

4 - 2 (x + 7) = 3 (x + 5)

5 x - 6 (x - 5) = 2 (x + 5) + (x - 4)

- 10 x - 10 (- x + 1) = 5 (5 x - 1) - 10

What is the answer to solvefor x,y=xp+p^2 ?
The answer to solvefor x,y=xp+p^2 is x=(y-p^2)/p ;\quad p\ne 0