What is the general solution for solvefor x,y=y^5+cos(x) ?

The general solution for solvefor x,y=y^5+cos(x) is x=arccos(y-y^5)+2pin,x=-arccos(y-y^5)+2pin

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solvefor x,y=y^5+cos(x)

solve for

x, y = y^{5} + cos (x)

x = arccos (y - y^{5}) + 2 πn, x = - arccos (y - y^{5}) + 2 πn

Solution steps

y = y^{5} + cos (x)

Switch sides

y^{5} + cos (x) = y

Move

y^{5}

to the right side

cos (x) = y - y^{5}

Apply trig inverse properties

x = arccos (y - y^{5}) + 2 πn, x = - arccos (y - y^{5}) + 2 πn

9 (x - 3) = 18

3 (x + 1) = 24

12 m + 3 (m - 1) = - 2 (m + 1) + 16

m L \cdot \frac{2 - 0}{1 - 3} = - 1

- 6 x + \frac{1}{2} (x - 1) - \frac{3}{2} = - 3 x

What is the general solution for solvefor x,y=y^5+cos(x) ?
The general solution for solvefor x,y=y^5+cos(x) is x=arccos(y-y^5)+2pin,x=-arccos(y-y^5)+2pin