What is the answer to (x+2}{12}+(2x-3)/9 =\frac{4-3x)/(10) ?

The answer to (x+2}{12}+(2x-3)/9 =\frac{4-3x)/(10) is x= 102/109

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(x+2}{12}+(2x-3)/9 =\frac{4-3x)/(10)

\frac{x + 2}{12} + \frac{2 x - 3}{9} = \frac{4 - 3 x}{10}

x = \frac{102}{109}

Decimal Notation

x = 0.93577 \dots

Solution steps

\frac{x + 2}{12} + \frac{2 x - 3}{9} = \frac{4 - 3 x}{10}

Multiply by LCM

15 (x + 2) + 20 (2 x - 3) = 18 (- 3 x + 4)

Expand

15 (x + 2) + 20 (2 x - 3) : 55 x - 30

Expand

18 (- 3 x + 4) : - 54 x + 72

55 x - 30 = - 54 x + 72

Move

30

to the right side

55 x = - 54 x + 102

Move

54 x

to the left side

109 x = 102

Divide both sides by

109

x = \frac{102}{109}

4 x - (- x + 1) + 1 = 6

5 (x + 5) - 2 (x + 3) = 3 (x + 1) + 4 (2 x - 1)

x, x y - y = 0

a, x = \frac{3 π}{4} r a d

\frac{2 x - 3}{3} - \frac{1 - 4 x}{5} = 1

What is the answer to (x+2}{12}+(2x-3)/9 =\frac{4-3x)/(10) ?
The answer to (x+2}{12}+(2x-3)/9 =\frac{4-3x)/(10) is x= 102/109
Solve for x: (x+2}{12}+(2x-3)/9 =\frac{4-3x)/(10)
The solution is x= 102/109