What is the answer to solvefor A,f=A¬ B¬ B¬+AB¬ C¬+ABC ?

The answer to solvefor A,f=A¬ B¬ B¬+AB¬ C¬+ABC is A= f/(B(B+2C));\quad B(B+2C)\ne 0

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solvefor A,f=A¬ B¬ B¬+AB¬ C¬+ABC

solve for

A, f = A \neg B \neg B \neg + A B \neg C \neg + A BC

A = \frac{f}{B ( B + 2 C )}; B (B + 2 C) \neq = 0

Solution steps

f = A \neg B \neg B \neg + A B \neg C \neg + A BC

Switch sides

A \neg B \neg B \neg + A B \neg C \neg + A BC = f

Simplify

A \neg B \neg B \neg + A B \neg C \neg + A BC : \neg \neg \neg A B^{2} + \neg \neg A BC + A BC

\neg \neg \neg A B^{2} + \neg \neg A BC + A BC = f

Factor

\neg \neg \neg A B^{2} + \neg \neg A BC + A BC : A B (B + 2 C)

A B (B + 2 C) = f

Divide both sides by

B (B + 2 C); B (B + 2 C) \neq = 0

A = \frac{f}{B ( B + 2 C )}; B (B + 2 C) \neq = 0

x = (5^{l o g_{6} (2)}) (5^{l o g_{6} (18)})

8 - 5 x = - 3 (2 x + 4)

2 x + y = y + 2 x

2 (x - 3 (x - 4 (x - (\frac{x}{8} + 1)))) = 1

(1 - x) \cdot 5 = 5

What is the answer to solvefor A,f=A¬ B¬ B¬+AB¬ C¬+ABC ?
The answer to solvefor A,f=A¬ B¬ B¬+AB¬ C¬+ABC is A= f/(B(B+2C));\quad B(B+2C)\ne 0