What is the answer to A=4(1+2i)-3(2-i)+(1-i)^2 ?

The answer to A=4(1+2i)-3(2-i)+(1-i)^2 is A=-2+9i

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A=4(1+2i)-3(2-i)+(1-i)^2

A = 4 (1 + 2 i) - 3 (2 - i) + (1 - i)^{2}

A = - 2 + 9 i

Solution steps

A = 4 (1 + 2 i) - 3 (2 - i) + (1 - i)^{2}

Simplify

4 (1 + 2 i) - 3 (2 - i) + (1 - i)^{2} : - 2 + 9 i

A = - 2 + 9 i

x, x + 4 y - 4 = 0

12 x - 8 = 10 x + 6

3 t = \frac{π 3}{2}

x, x + 4 y - 12 = 0

3 x - 10 = 6 - x

What is the answer to A=4(1+2i)-3(2-i)+(1-i)^2 ?
The answer to A=4(1+2i)-3(2-i)+(1-i)^2 is A=-2+9i