What is the answer to E=sqrt([(1/3)^2+(3/2)^{-2)]^{-1}+6 1/5} ?

The answer to E=sqrt([(1/3)^2+(3/2)^{-2)]^{-1}+6 1/5} is E=2sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

E=sqrt([(1/3)^2+(3/2)^{-2)]^{-1}+6 1/5}

E = [(\frac{1}{3})^{2} + (\frac{3}{2})^{- 2}]^{- 1} + 6 \frac{1}{5}

E = 22

Decimal Notation

E = 2.82842 \dots

Solution steps

E = [(\frac{1}{3})^{2} + (\frac{3}{2})^{- 2}]^{- 1} + 6 \frac{1}{5}

Convert mixed numbers to improper fractions:

6 \frac{1}{5} = \frac{31}{5}

E = [(\frac{1}{3})^{2} + (\frac{3}{2})^{- 2}]^{- 1} + \frac{31}{5}

Simplify

((\frac{1}{3})^{2} + (\frac{3}{2})^{- 2})^{- 1} + \frac{31}{5} : 22

E = 22

4 (x + 2) = 5 (x - 2) - 8

f = 2 (- 1) + 3

x, 2 y = 6 x

80 x + 10 = 30 x + 300

a, 5 a - 3 = 2 c + 12

What is the answer to E=sqrt([(1/3)^2+(3/2)^{-2)]^{-1}+6 1/5} ?
The answer to E=sqrt([(1/3)^2+(3/2)^{-2)]^{-1}+6 1/5} is E=2sqrt(2)
Solve for E: E=sqrt([(1/3)^2+(3/2)^{-2)]^{-1}+6 1/5}
The solution is E=2sqrt(2)