What is the answer to solvefor a,4=ae^0+be^{-4(0)}+3(0)e^{(0)} ?

The answer to solvefor a,4=ae^0+be^{-4(0)}+3(0)e^{(0)} is a=4-b

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor a,4=ae^0+be^{-4(0)}+3(0)e^{(0)}

solve for

a, 4 = a e^{0} + b e^{- 4 (0)} + 3 (0) e^{(0)}

a = 4 - b

Solution steps

4 = a e^{0} + b e^{- 4 (0)} + 3 (0) e^{(0)}

Switch sides

a e^{0} + b e^{- 4 \cdot 0} + 3 \cdot 0 e^{0} = 4

Simplify

a e^{0} + b e^{- 4 (0)} + 3 (0) e^{0} : a + b

a + b = 4

Move

b

to the right side

a = 4 - b

y = 6 + 4

3 x - 3 (x - 4) = 5 - x

2 x = \frac{3}{4}

(1 + 8)^{\frac{3}{2}} = (1 + 2)^{\frac{3}{2}} + C

6000 = 20 x - 4000

What is the answer to solvefor a,4=ae^0+be^{-4(0)}+3(0)e^{(0)} ?
The answer to solvefor a,4=ae^0+be^{-4(0)}+3(0)e^{(0)} is a=4-b