What is the answer to solvefor x,y^{(4)}(x)=x+2 ?

The answer to solvefor x,y^{(4)}(x)=x+2 is x= 2/(y^4-1);\quad y\ne 1,y\ne-1,y\ne i,y\ne-i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor x,y^{(4)}(x)=x+2

solve for

x, y^{(4)} (x) = x + 2

x = \frac{2}{y ^{4} - 1}; y \neq = 1, y \neq = - 1, y \neq = i, y \neq = - i

Solution steps

y^{(4)} (x) = x + 2

Expand

y^{4} (x) : x y^{4}

x y^{4} = x + 2

Move

x

to the left side

x y^{4} - x = 2

Factor

x y^{4} - x : x (y^{4} - 1)

x (y^{4} - 1) = 2

Divide both sides by

y^{4} - 1; y \neq = 1, y \neq = - 1, y \neq = i, y \neq = - i

x = \frac{2}{y ^{4} - 1}; y \neq = 1, y \neq = - 1, y \neq = i, y \neq = - i

(a x - b)^{2} = a^{2} x^{2} - b^{2}

4 x + 12 - x = 21

2 n - (- 4 + (n - 5)) = n - (n + 2)

35 x = 105

0.3 x - 0.5 = 0.2 x + 6

What is the answer to solvefor x,y^{(4)}(x)=x+2 ?
The answer to solvefor x,y^{(4)}(x)=x+2 is x= 2/(y^4-1);\quad y\ne 1,y\ne-1,y\ne i,y\ne-i