What is the answer to x^2-x-2=(x-2)(x+1) ?

The answer to x^2-x-2=(x-2)(x+1) is True for all x

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x^2-x-2=(x-2)(x+1)

x^{2} - x - 2 = (x - 2) (x + 1)

True for all x

Solution steps

x^{2} - x - 2 = (x - 2) (x + 1)

Expand

(x - 2) (x + 1) : x^{2} - x - 2

x^{2} - x - 2 = x^{2} - x - 2

Move

2

to the right side

x^{2} - x = x^{2} - x

Subtract

x^{2} - x

from both sides

x^{2} - x - (x^{2} - x) = x^{2} - x - (x^{2} - x)

Simplify

0 = 0

Both sides are equal

True for all x

x = e^{- 3}

\frac{5}{8} x = - 40

2 (4 m - 5) = 4 m + 2

5 x = 3 x + 10

2 - (2 - 3 X) = 2

What is the answer to x^2-x-2=(x-2)(x+1) ?
The answer to x^2-x-2=(x-2)(x+1) is True for all x
Solve for x: x^2-x-2=(x-2)(x+1)
The solution is True for all x