What is the answer to solvefor x,(x-k)^2=k^2-2x+x^2 ?

The answer to solvefor x,(x-k)^2=k^2-2x+x^2 is x=0

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solvefor x,(x-k)^2=k^2-2x+x^2

solve for

x, (x - k)^{2} = k^{2} - 2 x + x^{2}

x = 0

Solution steps

(x - k)^{2} = k^{2} - 2 x + x^{2}

Expand

(x - k)^{2} : x^{2} - 2 k x + k^{2}

x^{2} - 2 k x + k^{2} = k^{2} - 2 x + x^{2}

Move

k^{2}

to the right side

x^{2} - 2 k x = x^{2} - 2 x

Subtract

x^{2} - 2 x

from both sides

x^{2} - 2 k x - (x^{2} - 2 x) = x^{2} - 2 x - (x^{2} - 2 x)

Simplify

- 2 k x + 2 x = 0

Factor

- 2 k x + 2 x : 2 x (- k + 1)

2 x (- k + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0

a, 5 = 2 a - b

lo g_{\frac{1}{5}} (125) = - 3

0 = 39591 x - 5141

\frac{t}{5 ^{5}} = \frac{1}{5 ^{3}}

6 (4 x + 5) + 3 = 2 (10 x - 1)

What is the answer to solvefor x,(x-k)^2=k^2-2x+x^2 ?
The answer to solvefor x,(x-k)^2=k^2-2x+x^2 is x=0