What are the solutions to the equation (x-6)(x-2)=-4 ?

The solutions to the equation (x-6)(x-2)=-4 are x=4

Find the zeros of (x-6)(x-2)=-4

The zeros of (x-6)(x-2)=-4 are x=4

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(x - 6) (x - 2) = - 4

x = 4

Solution steps

(x - 6) (x - 2) = - 4

Expand

(x - 6) (x - 2) : x^{2} - 8 x + 12

x^{2} - 8 x + 12 = - 4

Move

4

to the left side

x^{2} - 8 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 16 = 0

x_{1, 2} = \frac{- ( - 8 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 8 )}{2 \cdot 1}

\frac{- ( - 8 )}{2 \cdot 1} = 4

x = 4

The solution to the quadratic equation is:

x = 4

\frac{x}{4} \leq \frac{9}{x}

\frac{2}{3} - \frac{2}{5}

2 m^{3} - m^{2} + 4 m - 2

∣ 5 - 5 x ∣ - 1 = 7

What are the solutions to the equation (x-6)(x-2)=-4 ?
The solutions to the equation (x-6)(x-2)=-4 are x=4
Find the zeros of (x-6)(x-2)=-4
The zeros of (x-6)(x-2)=-4 are x=4