What is the answer to (2x-(3x-4)+5x-6)+10x=12(x-1)+36 ?

The answer to (2x-(3x-4)+5x-6)+10x=12(x-1)+36 is x=13

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(2x-(3x-4)+5x-6)+10x=12(x-1)+36

(2 x - (3 x - 4) + 5 x - 6) + 10 x = 12 (x - 1) + 36

x = 13

Solution steps

(2 x - (3 x - 4) + 5 x - 6) + 10 x = 12 (x - 1) + 36

Remove parentheses:

(a) = a

2 x - (3 x - 4) + 5 x - 6 + 10 x = 12 (x - 1) + 36

Group like terms

2 x + 5 x + 10 x - (3 x - 4) - 6 = 12 (x - 1) + 36

Add similar elements:

2 x + 5 x + 10 x = 17 x

17 x - (3 x - 4) - 6 = 12 (x - 1) + 36

Expand

17 x - (3 x - 4) - 6 : 14 x - 2

Expand

12 (x - 1) + 36 : 12 x + 24

14 x - 2 = 12 x + 24

Move

2

to the right side

14 x = 12 x + 26

Move

12 x

to the left side

2 x = 26

Divide both sides by

2

x = 13

\frac{x}{2} + 4 = 5

x, 2 x + 3 y - z = 10

\frac{x}{2} + 3 = 0

50 t + 20 t = 21

2 (x + \frac{π}{2}) = 0

What is the answer to (2x-(3x-4)+5x-6)+10x=12(x-1)+36 ?
The answer to (2x-(3x-4)+5x-6)+10x=12(x-1)+36 is x=13
Solve for x: (2x-(3x-4)+5x-6)+10x=12(x-1)+36
The solution is x=13