What is the answer to solvefor y,yt+1-2yt=4t2^t ?

The answer to solvefor y,yt+1-2yt=4t2^t is y=-(2^{2+t}t-1)/t ;\quad t\ne 0

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solvefor y,yt+1-2yt=4t2^t

solve for

y, y t + 1 - 2 y t = 4 t 2^{t}

y = - \frac{2 ^{2 + t} t - 1}{t}; t \neq = 0

Solution steps

y t + 1 - 2 y t = 4 t \cdot 2^{t}

Simplify

y t + 1 - 2 y t : - t y + 1

Simplify

4 t \cdot 2^{t} : 2^{2 + t} t

- t y + 1 = 2^{2 + t} t

Move

1

to the right side

- t y = 2^{2 + t} t - 1

Divide both sides by

- t; t \neq = 0

y = - \frac{2 ^{2 + t} t - 1}{t}; t \neq = 0

5 x + 10 = 3 x - 6

25000 + 8 x = 44000 + 6 x

7 x + 4 = 0

360 + 180 (n - 2) = 1440

\frac{1}{2} x + 12 = 2 x

What is the answer to solvefor y,yt+1-2yt=4t2^t ?
The answer to solvefor y,yt+1-2yt=4t2^t is y=-(2^{2+t}t-1)/t ;\quad t\ne 0