What are the solutions to the equation 12x^2-6=x ?

The solutions to the equation 12x^2-6=x are x= 3/4 ,x=-2/3

Find the zeros of 12x^2-6=x

The zeros of 12x^2-6=x are x= 3/4 ,x=-2/3

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12 x^{2} - 6 = x

x = \frac{3}{4}, x = - \frac{2}{3}

Solution steps

12 x^{2} - 6 = x

Move

x

to the left side

12 x^{2} - 6 - x = 0

Write in the standard form

a x^{2} + b x + c = 0

12 x^{2} - x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 12 ( - 6 )}{2 \cdot 12}

(- 1)^{2} - 4 \cdot 12 (- 6) = 17

x_{1, 2} = \frac{- ( - 1 ) \pm 17}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 17}{2 \cdot 12}, x_{2} = \frac{- ( - 1 ) - 17}{2 \cdot 12}

x = \frac{- ( - 1 ) + 17}{2 \cdot 12} : \frac{3}{4}

x = \frac{- ( - 1 ) - 17}{2 \cdot 12} : - \frac{2}{3}

The solutions to the quadratic equation are:

x = \frac{3}{4}, x = - \frac{2}{3}

(- 5 + 4 i) (3 + i)

2 x^{2} + 7 x + 6

\frac{4 x - 5}{x + 3} \leq 3

∣ 5 x + 2 ∣ - 3 > 9

c^{2} + 5 c + 6

What are the solutions to the equation 12x^2-6=x ?
The solutions to the equation 12x^2-6=x are x= 3/4 ,x=-2/3
Find the zeros of 12x^2-6=x
The zeros of 12x^2-6=x are x= 3/4 ,x=-2/3