What is the answer to y+3-2 y/3+y/((2))= 4/((3))-3 y/2 ?

The answer to y+3-2 y/3+y/((2))= 4/((3))-3 y/2 is y=-5/7

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y+3-2 y/3+y/((2))= 4/((3))-3 y/2

y + 3 - 2 \frac{y}{3} + \frac{y}{( 2 )} = \frac{4}{( 3 )} - 3 \frac{y}{2}

y = - \frac{5}{7}

Decimal Notation

y = - 0.71428 \dots

Solution steps

y + 3 - 2 \cdot \frac{y}{3} + \frac{y}{( 2 )} = \frac{4}{( 3 )} - 3 \cdot \frac{y}{2}

Multiply

2 \cdot \frac{y}{3} : \frac{2 y}{3}

y + 3 - \frac{2 y}{3} + \frac{y}{2} = \frac{4}{( 3 )} - 3 \cdot \frac{y}{2}

Multiply

3 \cdot \frac{y}{2} : \frac{3 y}{2}

y + 3 - \frac{2 y}{3} + \frac{y}{2} = \frac{4}{3} - \frac{3 y}{2}

Move

\frac{3 y}{2}

to the left side

\frac{7 y}{3} + 3 = \frac{4}{3}

Move

3

to the right side

\frac{7 y}{3} = - \frac{5}{3}

Multiply both sides by

3

7 y = - 5

Divide both sides by

7

y = - \frac{5}{7}

\frac{5 - ( - 1 )}{2} - 2 = \frac{1 - ( - 1 )}{2} - \frac{2 ( - 1 + 1 )}{3}

\frac{x}{5} - \frac{5 + x}{20} = \frac{7}{16}

\frac{y}{3} + \frac{y}{4} = 7

x, x y = 200

6 x - 10 - 8 = 9 + 4 x - 4 x

What is the answer to y+3-2 y/3+y/((2))= 4/((3))-3 y/2 ?
The answer to y+3-2 y/3+y/((2))= 4/((3))-3 y/2 is y=-5/7
Solve for y: y+3-2 y/3+y/((2))= 4/((3))-3 y/2
The solution is y=-5/7