What is the answer to solvefor x,xy^2+4y^3-6x=0 ?

The answer to solvefor x,xy^2+4y^3-6x=0 is x=-(4y^3)/(y^2-6);\quad y\ne sqrt(6),y\ne-sqrt(6)

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solvefor x,xy^2+4y^3-6x=0

solve for

x, x y^{2} + 4 y^{3} - 6 x = 0

x = - \frac{4 y ^{3}}{y ^{2} - 6}; y \neq = 6, y \neq = - 6

Solution steps

x y^{2} + 4 y^{3} - 6 x = 0

Move

4 y^{3}

to the right side

x y^{2} - 6 x = - 4 y^{3}

Factor

x y^{2} - 6 x : x (y^{2} - 6)

x (y^{2} - 6) = - 4 y^{3}

Divide both sides by

y^{2} - 6; y \neq = 6, y \neq = - 6

x = - \frac{4 y ^{3}}{y ^{2} - 6}; y \neq = 6, y \neq = - 6

2 x + 8 - 9 x = 7 + 2 x + (- 2)

- 3 (x + 1) - 2 = 2 x + 5

2 x - 2 = 3 x - 6

- 9 - \frac{7}{11} y = 19

x, - \frac{2}{3} x + \frac{1}{3} y + \frac{1}{4} = - 2 x

What is the answer to solvefor x,xy^2+4y^3-6x=0 ?
The answer to solvefor x,xy^2+4y^3-6x=0 is x=-(4y^3)/(y^2-6);\quad y\ne sqrt(6),y\ne-sqrt(6)