What is the answer to 7x-(2[3-4(x+7)+5x])-8=17(x-1) ?

The answer to 7x-(2[3-4(x+7)+5x])-8=17(x-1) is x= 59/12

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7x-(2[3-4(x+7)+5x])-8=17(x-1)

7 x - (2 [3 - 4 (x + 7) + 5 x]) - 8 = 17 (x - 1)

x = \frac{59}{12}

Decimal Notation

x = 4.91666 \dots

Solution steps

7 x - (2 [3 - 4 (x + 7) + 5 x]) - 8 = 17 (x - 1)

7 x - 2 (3 - 4 (x + 7) + 5 x) - 8 = 17 (x - 1)

Expand

7 x - 2 (3 - 4 (x + 7) + 5 x) - 8 : 5 x + 42

Expand

17 (x - 1) : 17 x - 17

5 x + 42 = 17 x - 17

Move

42

to the right side

5 x = 17 x - 59

Move

17 x

to the left side

- 12 x = - 59

Divide both sides by

- 12

x = \frac{59}{12}

x + 66.73273 = 126.451

x, 9 y - 3 x - 4 = 0

10 + \frac{3}{4} y = 43

- 4 (d + 3) - 5 [3 d - 2 (2 d + 7)] - 8 = - 10 d - 6

\frac{w}{5} - \frac{11}{20} = \frac{w}{4}

What is the answer to 7x-(2[3-4(x+7)+5x])-8=17(x-1) ?
The answer to 7x-(2[3-4(x+7)+5x])-8=17(x-1) is x= 59/12
Solve for x: 7x-(2[3-4(x+7)+5x])-8=17(x-1)
The solution is x= 59/12