What is the answer to solvefor E,y=(E-E_{0})/(kT) ?

The answer to solvefor E,y=(E-E_{0})/(kT) is E=ykT+E_{0};\quad k\ne 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor E,y=(E-E_{0})/(kT)

solve for

E, y = \frac{E - E _{0}}{k T}

E = y k T + E_{0}; k \neq = 0

Solution steps

y = \frac{E - E _{0}}{k T}

Switch sides

\frac{E - E _{0}}{k T} = y

Multiply both sides by

k T

E - E_{0} = y k T; k \neq = 0

Move

E_{0}

to the right side

E = y k T + E_{0}; k \neq = 0

p (- 3) = 2, p (- 1) = 2, p (0) - 1, p (1) = - 1, p (3) = 1

7 x - 2 = - 4 x + 13

n, s = (n - 2) \cdot 180

\frac{2}{3} y + \frac{16}{21} = \frac{6}{7}

x, 5 x + y = 21

What is the answer to solvefor E,y=(E-E_{0})/(kT) ?
The answer to solvefor E,y=(E-E_{0})/(kT) is E=ykT+E_{0};\quad k\ne 0