What is the answer to a=(x^2+x+4)(x^2+x+5)-(x^2+x+3)(x^2+x+6) ?

The answer to a=(x^2+x+4)(x^2+x+5)-(x^2+x+3)(x^2+x+6) is True for all x;\quad 2=a

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a=(x^2+x+4)(x^2+x+5)-(x^2+x+3)(x^2+x+6)

a = (x^{2} + x + 4) (x^{2} + x + 5) - (x^{2} + x + 3) (x^{2} + x + 6)

True for all x; 2 = a

Solution steps

a = (x^{2} + x + 4) (x^{2} + x + 5) - (x^{2} + x + 3) (x^{2} + x + 6)

Switch sides

(x^{2} + x + 4) (x^{2} + x + 5) - (x^{2} + x + 3) (x^{2} + x + 6) = a

Expand

(x^{2} + x + 4) (x^{2} + x + 5) - (x^{2} + x + 3) (x^{2} + x + 6) : 2

2 = a

Both sides are equal

True for all x; 2 = a

- 2 (3) + 20 (- 1) + 30 (2) = 53

- 2 (p - 3) = 5 (- 2 - 2 p)

\frac{x}{2} + 3 + x + 9 = 60

x, f = g \cdot h + 2 \cdot j (x)

4 - k + 3 = 2 (3 - 2 k)

What is the answer to a=(x^2+x+4)(x^2+x+5)-(x^2+x+3)(x^2+x+6) ?
The answer to a=(x^2+x+4)(x^2+x+5)-(x^2+x+3)(x^2+x+6) is True for all x;\quad 2=a