What is the answer to (2(x-3))/7-(1-6x}{14}+\frac{5(x-2))/2 =1 ?

The answer to (2(x-3))/7-(1-6x}{14}+\frac{5(x-2))/2 =1 is x= 97/45

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(2(x-3))/7-(1-6x}{14}+\frac{5(x-2))/2 =1

\frac{2 ( x - 3 )}{7} - \frac{1 - 6 x}{14} + \frac{5 ( x - 2 )}{2} = 1

x = \frac{97}{45}

Decimal Notation

x = 2.15555 \dots

Solution steps

\frac{2 ( x - 3 )}{7} - \frac{1 - 6 x}{14} + \frac{5 ( x - 2 )}{2} = 1

Multiply by LCM

4 (x - 3) - (1 - 6 x) + 35 (x - 2) = 14

Expand

4 (x - 3) - (1 - 6 x) + 35 (x - 2) : 45 x - 83

45 x - 83 = 14

Move

83

to the right side

45 x = 97

Divide both sides by

45

x = \frac{97}{45}

3 b - 5 = 13

F, D = \frac{2}{3} (F + G)

z, 2 y + 2 zy = 0

y = - 0 + 5

(y + 2)^{2} - 4 (y - 3) = (y - 3)^{2} - 3 (1 - y)

What is the answer to (2(x-3))/7-(1-6x}{14}+\frac{5(x-2))/2 =1 ?
The answer to (2(x-3))/7-(1-6x}{14}+\frac{5(x-2))/2 =1 is x= 97/45
Solve for x: (2(x-3))/7-(1-6x}{14}+\frac{5(x-2))/2 =1
The solution is x= 97/45