What is the answer to 2(x^2+2)+3x=x+2x^2 ?

The answer to 2(x^2+2)+3x=x+2x^2 is x=-2

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2(x^2+2)+3x=x+2x^2

2 (x^{2} + 2) + 3 x = x + 2 x^{2}

x = - 2

Solution steps

2 (x^{2} + 2) + 3 x = x + 2 x^{2}

Expand

2 (x^{2} + 2) : 2 x^{2} + 4

2 x^{2} + 4 + 3 x = x + 2 x^{2}

Move

4

to the right side

2 x^{2} + 3 x = x + 2 x^{2} - 4

Subtract

x + 2 x^{2}

from both sides

2 x^{2} + 3 x - (x + 2 x^{2}) = x + 2 x^{2} - 4 - (x + 2 x^{2})

Simplify

2 x = - 4

Divide both sides by

2

x = - 2

2 (+ \frac{1}{16}) + \frac{3}{4} = 6 (+ \frac{1}{16}) + \frac{1}{2}

3 z + \frac{z}{1 + i} = 10 - 4 i

p, 4 p = 5 q

x, 2 (x - 3) - 3 (y + 2) + 5 (z - 5) = 0

x + 0.2 x = 750

What is the answer to 2(x^2+2)+3x=x+2x^2 ?
The answer to 2(x^2+2)+3x=x+2x^2 is x=-2
Solve for x: 2(x^2+2)+3x=x+2x^2
The solution is x=-2