What is factor ((y^2)/6-3/(2y^2))^2+1 ?

The solution to factor ((y^2)/6-3/(2y^2))^2+1 is 1/2+(y^4)/(36)+9/(4y^4)

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factor ((y^2)/6-3/(2y^2))^2+1

factor

(\frac{y ^{2}}{6} - \frac{3}{2 y ^{2}})^{2} + 1

\frac{1}{2} + \frac{y ^{4}}{36} + \frac{9}{4 y ^{4}}

Solution steps

(\frac{y ^{2}}{6} - \frac{3}{2 y ^{2}})^{2} + 1

(\frac{y ^{2}}{6} - \frac{3}{2 y ^{2}})^{2} : \frac{y ^{4}}{36} - \frac{1}{2} + \frac{9}{4 y ^{4}}

= \frac{y ^{4}}{36} - \frac{1}{2} + \frac{9}{4 y ^{4}} + 1

Combine the fractions

1 - \frac{1}{2} : \frac{1}{2}

= \frac{1}{2} + \frac{y ^{4}}{36} + \frac{9}{4 y ^{4}}

1 \cdot 1 0^{- 3}

12 (x - 3) - 35 (2 x - 5) = 3 - 34 (2 x - 6)

14 x - 21 x^{2}

x^{2} - 6 x = 3

p^{2} + 11 p + 10

What is factor ((y^2)/6-3/(2y^2))^2+1 ?
The solution to factor ((y^2)/6-3/(2y^2))^2+1 is 1/2+(y^4)/(36)+9/(4y^4)