What are the solutions to the equation x^2-9x-20=0 ?

The solutions to the equation x^2-9x-20=0 are x=(9+sqrt(161))/2 ,x=(9-sqrt(161))/2

Find the zeros of x^2-9x-20=0

The zeros of x^2-9x-20=0 are x=(9+sqrt(161))/2 ,x=(9-sqrt(161))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 9 x - 20 = 0

x = \frac{9 + 161}{2}, x = \frac{9 - 161}{2}

Decimal Notation

x = 10.84428 \dots, x = - 1.84428 \dots

Solution steps

x^{2} - 9 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot (- 20) = 161

x_{1, 2} = \frac{- ( - 9 ) \pm 161}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 161}{2 \cdot 1}, x_{2} = \frac{- ( - 9 ) - 161}{2 \cdot 1}

x = \frac{- ( - 9 ) + 161}{2 \cdot 1} : \frac{9 + 161}{2}

x = \frac{- ( - 9 ) - 161}{2 \cdot 1} : \frac{9 - 161}{2}

The solutions to the quadratic equation are:

x = \frac{9 + 161}{2}, x = \frac{9 - 161}{2}

2 x^{2} + 5 x - 3 > 0

22 \geq 4 m - 2 or 5 - 3 m \leq - 13

x^{- 1}

(8 t - 16)^{2}

\frac{v}{5} = 9

What are the solutions to the equation x^2-9x-20=0 ?
The solutions to the equation x^2-9x-20=0 are x=(9+sqrt(161))/2 ,x=(9-sqrt(161))/2
Find the zeros of x^2-9x-20=0
The zeros of x^2-9x-20=0 are x=(9+sqrt(161))/2 ,x=(9-sqrt(161))/2