What is the answer to solvefor a,v^2=vo^2+2ax ?

The answer to solvefor a,v^2=vo^2+2ax is a=(v^2-vo^2)/(2x);\quad x\ne 0

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solvefor a,v^2=vo^2+2ax

solve for

a, v^{2} = v o^{2} + 2 a x

a = \frac{v ^{2} - v o ^{2}}{2 x}; x \neq = 0

Solution steps

v^{2} = v o^{2} + 2 a x

Switch sides

v o^{2} + 2 a x = v^{2}

Move

v o^{2}

to the right side

2 a x = v^{2} - v o^{2}

Divide both sides by

2 x; x \neq = 0

a = \frac{v ^{2} - v o ^{2}}{2 x}; x \neq = 0

x, 2 y = 3 x + 2

11 - 7 x = 3 + 3 x

l, x^{x} (ln (x) + 1) = 1

16 - x = 0

f, \frac{f}{x + 2} = (x^{2} - 7 x + 2) + \frac{5}{x + 2}

What is the answer to solvefor a,v^2=vo^2+2ax ?
The answer to solvefor a,v^2=vo^2+2ax is a=(v^2-vo^2)/(2x);\quad x\ne 0