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Popular >

ax+b^2=a^2+bx,a\ne b

Solution

a x + b^{2} = a^{2} + b x, a \neq = b

Solution

x = a + b; a \neq = b

Solution steps

a x + b^{2} = a^{2} + b x

Move

b^{2}

to the right side

a x = a^{2} + b x - b^{2}

Move

b x

to the left side

a x - b x = a^{2} - b^{2}

Factor

a x - b x : x (a - b)

x (a - b) = a^{2} - b^{2}

Divide both sides by

a - b; a \neq = b

x = a + b; a \neq = b

Popular Examples

3 (x + 4) = 21

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x, ∣ z ∣ i + x + y = 2 i

solvefor x,-5(x+2y)-3/2+x=y solve for

x, - 5 (x + 2 y) - \frac{3}{2} + x = y

3.9 x - 0.7 = 8.66

solvefor x,2x+4y=-1 solve for

x, 2 x + 4 y = - 1

Frequently Asked Questions (FAQ)

What is the answer to ax+b^2=a^2+bx,a\ne b ?
The answer to ax+b^2=a^2+bx,a\ne b is x=a+b;\quad a\ne b