What is the answer to (2y+3)/3 =(3y-1)/6 ?

The answer to (2y+3)/3 =(3y-1)/6 is y=-7

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(2y+3)/3 =(3y-1)/6

\frac{2 y + 3}{3} = \frac{3 y - 1}{6}

y = - 7

Solution steps

\frac{2 y + 3}{3} = \frac{3 y - 1}{6}

Apply fraction cross multiply: if

\frac{a}{b} = \frac{c}{d}

then

a \cdot d = b \cdot c

(2 y + 3) \cdot 6 = 3 (3 y - 1)

Expand

(2 y + 3) \cdot 6 : 12 y + 18

Expand

3 (3 y - 1) : 9 y - 3

12 y + 18 = 9 y - 3

Move

18

to the right side

12 y = 9 y - 21

Move

9 y

to the left side

3 y = - 21

Divide both sides by

3

y = - 7

3 x - 5 = 5 x - 17

\frac{( x + 2 )}{2} = \frac{( 3 x - 8 )}{10}

\frac{29 - 2 x}{3} = 5

2 (x - 5) + 3 (x - 2) = 0

x, 4 x - 5 y + 10 = 0

What is the answer to (2y+3)/3 =(3y-1)/6 ?
The answer to (2y+3)/3 =(3y-1)/6 is y=-7
Solve for y: (2y+3)/3 =(3y-1)/6
The solution is y=-7