What is the answer to solvefor x,(y+1)^2=-8(x-2)y ?

The answer to solvefor x,(y+1)^2=-8(x-2)y is x=-((y+1)^2)/(8y)+2;\quad y\ne 0

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solvefor x,(y+1)^2=-8(x-2)y

solve for

x, (y + 1)^{2} = - 8 (x - 2) y

x = - \frac{( y + 1 ) ^{2}}{8 y} + 2; y \neq = 0

Solution steps

(y + 1)^{2} = - 8 (x - 2) y

Switch sides

- 8 (x - 2) y = (y + 1)^{2}

Divide both sides by

- 8 y; y \neq = 0

x - 2 = - \frac{( y + 1 ) ^{2}}{8 y}; y \neq = 0

Move

2

to the right side

x = - \frac{( y + 1 ) ^{2}}{8 y} + 2; y \neq = 0

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x, y - \frac{9}{e ^{2}} = - \frac{3}{e ^{2}} (x - 3)

92 x + 1 = 93 x - 2

2 x - 11 = - 33

5 x - 10 = x - 2

What is the answer to solvefor x,(y+1)^2=-8(x-2)y ?
The answer to solvefor x,(y+1)^2=-8(x-2)y is x=-((y+1)^2)/(8y)+2;\quad y\ne 0