What are the solutions to the equation -6x^2+6x-162=0 ?

The solutions to the equation -6x^2+6x-162=0 are x= 1/2-i(sqrt(107))/2 ,x= 1/2+i(sqrt(107))/2

Find the zeros of -6x^2+6x-162=0

The zeros of -6x^2+6x-162=0 are x= 1/2-i(sqrt(107))/2 ,x= 1/2+i(sqrt(107))/2

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- 6 x^{2} + 6 x - 162 = 0

x = \frac{1}{2} - i \frac{107}{2}, x = \frac{1}{2} + i \frac{107}{2}

Solution steps

- 6 x^{2} + 6 x - 162 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 6 ) ( - 162 )}{2 ( - 6 )}

Simplify

6^{2} - 4 (- 6) (- 162) : 6107 i

x_{1, 2} = \frac{- 6 \pm 6 107 i}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- 6 + 6 107 i}{2 ( - 6 )}, x_{2} = \frac{- 6 - 6 107 i}{2 ( - 6 )}

x = \frac{- 6 + 6 107 i}{2 ( - 6 )} : \frac{1}{2} - i \frac{107}{2}

x = \frac{- 6 - 6 107 i}{2 ( - 6 )} : \frac{1}{2} + i \frac{107}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2} - i \frac{107}{2}, x = \frac{1}{2} + i \frac{107}{2}

12 w - 24 = 12

\frac{( 8 c d ^{3} ) ( - 3 c ^{4} )}{6 c ^{2} d} - 9 c^{3} d^{2}

x^{2} y + x^{4} y^{3}

9 = \frac{1}{2} (5 x + 6)

4 x^{2} + 15 x = 7 x - 3

What are the solutions to the equation -6x^2+6x-162=0 ?
The solutions to the equation -6x^2+6x-162=0 are x= 1/2-i(sqrt(107))/2 ,x= 1/2+i(sqrt(107))/2
Find the zeros of -6x^2+6x-162=0
The zeros of -6x^2+6x-162=0 are x= 1/2-i(sqrt(107))/2 ,x= 1/2+i(sqrt(107))/2