What is the answer to solvefor x,v^2=v0^2+2ax ?

The answer to solvefor x,v^2=v0^2+2ax is x=(v^2)/(2a);\quad a\ne 0

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solvefor x,v^2=v0^2+2ax

solve for

x, v^{2} = v 0^{2} + 2 a x

x = \frac{v ^{2}}{2 a}; a \neq = 0

Solution steps

v^{2} = v \cdot 0^{2} + 2 a x

Switch sides

v \cdot 0^{2} + 2 a x = v^{2}

Apply rule

0^{a} = 0

0^{2} = 0

0 \cdot v + 2 a x = v^{2}

Apply rule

0 \cdot a = 0

0 + 2 a x = v^{2}

0 + 2 a x = 2 a x

2 a x = v^{2}

Divide both sides by

2 a; a \neq = 0

x = \frac{v ^{2}}{2 a}; a \neq = 0

π = \frac{2 π f}{48000}

11 x + 21 = 9 x + 33

5 + 3 x = 35

v - 8 = - 6

\frac{x}{50} = \frac{5.5}{1}

What is the answer to solvefor x,v^2=v0^2+2ax ?
The answer to solvefor x,v^2=v0^2+2ax is x=(v^2)/(2a);\quad a\ne 0