What is the answer to solvefor y,3x-4y+12=0 ?

The answer to solvefor y,3x-4y+12=0 is y=-(-3x-12)/4

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solvefor y,3x-4y+12=0

solve for

y, 3 x - 4 y + 12 = 0

y = - \frac{- 3 x - 12}{4}

Solution steps

3 x - 4 y + 12 = 0

Move

3 x

to the right side

- 4 y + 12 = - 3 x

Move

12

to the right side

- 4 y = - 3 x - 12

Divide both sides by

- 4

y = - \frac{- 3 x - 12}{4}

a, 2 b - a = 6

E = 3 6^{\circ} + \frac{π}{5}

- 8 c + 13 = - 10 c - 9

\frac{7 x}{9} + \frac{1}{3} = \frac{x - 1}{2}

x, f (2) = 7 x - 3

What is the answer to solvefor y,3x-4y+12=0 ?
The answer to solvefor y,3x-4y+12=0 is y=-(-3x-12)/4