What is the answer to (4x-3)/6-(3x-1)/4 =(4x-2)/3-1 ?

The answer to (4x-3)/6-(3x-1)/4 =(4x-2)/3-1 is x=1

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(4x-3)/6-(3x-1)/4 =(4x-2)/3-1

\frac{4 x - 3}{6} - \frac{3 x - 1}{4} = \frac{4 x - 2}{3} - 1

x = 1

Solution steps

\frac{4 x - 3}{6} - \frac{3 x - 1}{4} = \frac{4 x - 2}{3} - 1

Multiply by LCM

2 (4 x - 3) - 3 (3 x - 1) = 4 (4 x - 2) - 12

Expand

2 (4 x - 3) - 3 (3 x - 1) : - x - 3

Expand

4 (4 x - 2) - 12 : 16 x - 20

- x - 3 = 16 x - 20

Move

3

to the right side

- x = 16 x - 17

Move

16 x

to the left side

- 17 x = - 17

Divide both sides by

- 17

x = 1

x, P = 2 x 4 - x 3 + 2 x 2 - k

x - (7 - x) = 5 (x + 1) + x

85 = 191 - U

x, 5 y = 8 x

4 (\frac{2 - 7 y}{21}) + y = 1

What is the answer to (4x-3)/6-(3x-1)/4 =(4x-2)/3-1 ?
The answer to (4x-3)/6-(3x-1)/4 =(4x-2)/3-1 is x=1
Solve for x: (4x-3)/6-(3x-1)/4 =(4x-2)/3-1
The solution is x=1