What is the answer to solvefor x,xy-2/3 x+13y-26/3 =260 ?

The answer to solvefor x,xy-2/3 x+13y-26/3 =260 is x=(-39y+806)/(3y-2);\quad y\ne 2/3

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solvefor x,xy-2/3 x+13y-26/3 =260

solve for

x, x y - \frac{2}{3} x + 13 y - \frac{26}{3} = 260

x = \frac{- 39 y + 806}{3 y - 2}; y \neq = \frac{2}{3}

Solution steps

x y - \frac{2}{3} x + 13 y - \frac{26}{3} = 260

Move

13 y

to the right side

x y - \frac{2}{3} x - \frac{26}{3} = 260 - 13 y

Move

\frac{26}{3}

to the right side

x y - \frac{2}{3} x = - 13 y + \frac{806}{3}

Multiply both sides by

3

3 x y - 2 x = - 39 y + 806

Factor

3 x y - 2 x : x (3 y - 2)

x (3 y - 2) = - 39 y + 806

Divide both sides by

3 y - 2; y \neq = \frac{2}{3}

x = \frac{- 39 y + 806}{3 y - 2}; y \neq = \frac{2}{3}

\frac{1}{4} x + \frac{1}{2} x = 6

- 10 + 3 = 3 + (- 10)

(5 \cdot 1 0^{5})^{2} = (2 \cdot 1 0^{6})^{2} + 2 (- 87816 \cdot 1 0^{14}) X

10 + 10 (x + 3) = - x - 10 (- x + 1)

- 4 (- 2 x + 5) - 5 x + 5 = - 24 - 24

What is the answer to solvefor x,xy-2/3 x+13y-26/3 =260 ?
The answer to solvefor x,xy-2/3 x+13y-26/3 =260 is x=(-39y+806)/(3y-2);\quad y\ne 2/3