What is ((2-2x))/(5x+2)<= 0 ?

The solution to ((2-2x))/(5x+2) = 1

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((2-2x))/(5x+2)<= 0

\frac{( 2 - 2 x )}{5 x + 2} \leq 0

x < - \frac{2}{5} or x \geq 1

Interval Notation

(- \infty, - \frac{2}{5}) \cup [1, \infty)

Decimal Notation

x < - 0.4 or x \geq 1

Solution steps

\frac{2 - 2 x}{5 x + 2} \leq 0

Factor

\frac{2 - 2 x}{5 x + 2} : \frac{- 2 ( x - 1 )}{5 x + 2}

\frac{- 2 ( x - 1 )}{5 x + 2} \leq 0

Multiply both sides by

- 1

(reverse the inequality)

\frac{( - 2 ( x - 1 ) ) ( - 1 )}{5 x + 2} \geq 0 \cdot (- 1)

Simplify

\frac{2 ( x - 1 )}{5 x + 2} \geq 0

Divide both sides by

2

\frac{\frac{2 ( x - 1 )}{5 x + 2}}{2} \geq \frac{0}{2}

Simplify

\frac{x - 1}{5 x + 2} \geq 0

Identify the intervals

x < - \frac{2}{5} or x \geq 1

- 10 (x - 2) = 200

y^{2} + 6 y + 34 = 0

x + \frac{x + 1}{5} = x + \frac{x}{2}

- x + 3 = x^{2} + 1

- 60 \cdot 4 \cdot 8 i \cdot (7 i)^{3}

What is ((2-2x))/(5x+2)<= 0 ?
The solution to ((2-2x))/(5x+2)<= 0 is x<-2/5 \lor x>= 1