What is factor 8h^6-27j^9 ?

The solution to factor 8h^6-27j^9 is (2h^2-3j^3)(9j^6+4h^4+6h^2j^3)

Popular >

factor 8h^6-27j^9

factor

8 h^{6} - 27 j^{9}

(2 h^{2} - 3 j^{3}) (9 j^{6} + 4 h^{4} + 6 h^{2} j^{3})

Solution steps

8 h^{6} - 27 j^{9}

Apply exponent rules

= (2 h^{2})^{3} - (3 j^{3})^{3}

Apply Difference of Cubes Formula:

x^{3} - y^{3} = (x - y) (x^{2} + x y + y^{2})

(2 h^{2})^{3} - (3 j^{3})^{3} = (2 h^{2} - 3 j^{3}) ((2 h^{2})^{2} + 2 h^{2} \cdot 3 j^{3} + (3 j^{3})^{2})

= (2 h^{2} - 3 j^{3}) ((2 h^{2})^{2} + 2 h^{2} \cdot 3 j^{3} + (3 j^{3})^{2})

Simplify

(2 h^{2})^{2} + 2 h^{2} \cdot 3 j^{3} + (3 j^{3})^{2} : 4 h^{4} + 6 h^{2} j^{3} + 9 j^{6}

= (2 h^{2} - 3 j^{3}) (4 h^{4} + 6 h^{2} j^{3} + 9 j^{6})

= (2 h^{2} - 3 j^{3}) (9 j^{6} + 4 h^{4} + 6 h^{2} j^{3})

\frac{( - 4 x ^{5} + x ^{4} + 6 x ^{3} + 2 x ^{2} + 56 )}{( x - 2 )}

lo g_{10} (x) - 3 lo g_{10} (2 x) + 2 lo g_{10} (4 x)

582 x^{2} - 9 x^{2}

5 c^{1} + 5 c^{3}

\frac{\frac{2}{2}}{x}

What is factor 8h^6-27j^9 ?
The solution to factor 8h^6-27j^9 is (2h^2-3j^3)(9j^6+4h^4+6h^2j^3)