What is ((16a^4b^{10})^{-1})/2 ?

The solution to ((16a^4b^{10})^{-1})/2 is 1/(32a^4b^{10)}

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simplify ((16a^4b^{10})^{-1})/2

simplify

\frac{( 16 a ^{4} b ^{10} ) ^{- 1}}{2}

\frac{1}{32 a ^{4} b ^{10}}

Solution steps

\frac{( 16 a ^{4} b ^{10} ) ^{- 1}}{2}

Simplify

(16 a^{4} b^{10})^{- 1} : 1 6^{- 1} \cdot \frac{1}{a ^{4}} \cdot \frac{1}{b ^{10}}

= \frac{1 6 ^{- 1} \cdot \frac{1}{a ^{4}} \cdot \frac{1}{b ^{10}}}{2}

Factor

1 6^{- 1} : 2^{- 4}

= \frac{2 ^{- 4} \cdot \frac{1}{a ^{4}} \cdot \frac{1}{b ^{10}}}{2}

\frac{2 ^{- 4}}{2} = \frac{1}{2 ^{5}}

= \frac{\frac{1}{a ^{4}} \cdot \frac{1}{b ^{10}}}{2 ^{5}}

Simplify

\frac{\frac{1}{a ^{4}} \cdot \frac{1}{b ^{10}}}{2 ^{5}} : \frac{1}{a ^{4} b ^{10} \cdot 32}

= \frac{1}{a ^{4} b ^{10} \cdot 32}

= \frac{1}{32 a ^{4} b ^{10}}

(2 p + q)^{3}

6 x^{2} - 3 - 7 x

cos^{2} (a) - cos^{2} (b)

(4 x^{2} + 5) (3 x^{2} + 2)

(\frac{x + 1}{3})^{3}

What is ((16a^4b^{10})^{-1})/2 ?
The solution to ((16a^4b^{10})^{-1})/2 is 1/(32a^4b^{10)}