What is ((sin(1))/2 x-(cos(1))/2 x)^2 ?

The solution to ((sin(1))/2 x-(cos(1))/2 x)^2 is ((sin(1)-cos(1))^2x^2)/4

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simplify ((sin(1))/2 x-(cos(1))/2 x)^2

simplify

(\frac{sin ( 1 )}{2} x - \frac{cos ( 1 )}{2} x)^{2}

\frac{( sin ( 1 ) - cos ( 1 ) ) ^{2} x ^{2}}{4}

Solution steps

(\frac{sin ( 1 )}{2} x - \frac{cos ( 1 )}{2} x)^{2}

Simplify

\frac{sin ( 1 )}{2} x - \frac{cos ( 1 )}{2} x : \frac{x ( sin ( 1 ) - cos ( 1 ) )}{2}

= (\frac{x ( sin ( 1 ) - cos ( 1 ) )}{2})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( x ( sin ( 1 ) - cos ( 1 ) ) ) ^{2}}{2 ^{2}}

2^{2} = 4

= \frac{( x ( sin ( 1 ) - cos ( 1 ) ) ) ^{2}}{4}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

= \frac{( sin ( 1 ) - cos ( 1 ) ) ^{2} x ^{2}}{4}

77 x^{4} + 170 x^{2} + 77

\frac{2 x ^{- 3}}{y ^{5}}

sin^{2} (a) - sin^{2} (b)

- 2 k^{5} + k^{10} + 1

\frac{( cos ^{2} ( a ) )}{( sin ( a ) ) + sin ( a )}

What is ((sin(1))/2 x-(cos(1))/2 x)^2 ?
The solution to ((sin(1))/2 x-(cos(1))/2 x)^2 is ((sin(1)-cos(1))^2x^2)/4